2 tons hr oil steam boiler Coal Fired Chain stoker
HOT
Capacity:1-20t/h
Rated thermal efficiency: 100-104%
Fixed working pressure: ≤1.6MPa
Applicable fuel:natural gas etc.
HOT
Capacity:0.7-14MW
Rated thermal efficiency:96-98%
Fixed working pressure:≤1.25MPa
Applicable fuel:Natural gas, light oil, etc.
HOT
Capacity:0.7-2.8Mw
Rated thermal efficiency: 97.2-106%
Fixed working pressure:0.1MPa
Applicable fuel:Natural gas, etc.
HOT
Capacity:2.8-7.0Mw
Rated thermal efficiency:≥105.5%
Fixed working pressure:-0.02MPa
Applicable fuel:Natural gas, etc.
HOT
Capacity:99Kw
Rated thermal efficiency:97.2-104.4%
Fixed working pressure:1.0MPa
Applicable fuel:Natural gas, etc.
HOT
Capacity:0.5-4.0 t/h
Rated thermal efficiency:98%
Fixed working pressure:≤1.25MPa
Applicable fuel:electric energy
Steam leaves the superheater at 4.5 MPa and 320 °C. if the coal used has a heating value of 30,000 kJ/kg, calculate the no. of tons of coal fired per hr for a gross efficiency of 85%. Answer: A A. 4.889 tons/hr B. 5.897 tons/hr C. 3.267 tons/hr D. 2.675 tons/hr. 6. A water tube boiler has a capacity of 1000 kg/hr of steam.Get Price
2. BOILERS Bureau of Energy Efficiency 27 Syllabus Boilers: Types, Combustion in boilers, Performances evaluation, Analysis of losses, Feed water treatment, Blow down, Energy conservation opportunities. 2.1 Introduction A boiler is an enclosed vessel that provides a means for combustion heat to be transferred into water until it becomes heated water or steam.Get Price
For example: (i) Central thermal power plants, captive power plants based on coal. (ii) Nuclear power plants. Steam out Water in Q5–2 Boiler q1–2 = w1–2 (h2 – h1) + (kE2 – kE1) + PE2 – pE1) – q1–2 = h2 – h1 Heat is lost by the system to the cooling water q1–2 = h1 – h2 2. Steam flow rate = 3600Kg/hr = 3600/3600 = 1 Get Price
2. BOILERS Bureau of Energy Efficiency 27 Syllabus Boilers: Types, Combustion in boilers, Performances evaluation, Analysis of losses, Feed water treatment, Blow down, Energy conservation opportunities. 2.1 Introduction A boiler is an enclosed vessel that provides a means for combustion heat to be transferred into water until it becomes heated water or steam.Get Price
2. BOILERS Bureau of Energy Efficiency 27 Syllabus Boilers: Types, Combustion in boilers, Performances evaluation, Analysis of losses, Feed water treatment, Blow down, Energy conservation opportunities. 2.1 Introduction A boiler is an enclosed vessel that provides a means for combustion heat to be transferred into water until it becomes heated water or steam.Get Price
Steam leaves the superheater at 4.5 MPa and 320 °C. if the coal used has a heating value of 30,000 kJ/kg, calculate the no. of tons of coal fired per hr for a gross efficiency of 85%. Answer: A A. 4.889 tons/hr B. 5.897 tons/hr C. 3.267 tons/hr D. 2.675 tons/hr. 6. A water tube boiler has a capacity of 1000 kg/hr of steam.Get Price
For example: (i) Central thermal power plants, captive power plants based on coal. (ii) Nuclear power plants. Steam out Water in Q5–2 Boiler q1–2 = w1–2 (h2 – h1) + (kE2 – kE1) + PE2 – pE1) – q1–2 = h2 – h1 Heat is lost by the system to the cooling water q1–2 = h1 – h2 2. Steam flow rate = 3600Kg/hr = 3600/3600 = 1 Get Price
Steam leaves the superheater at 4.5 MPa and 320 °C. if the coal used has a heating value of 30,000 kJ/kg, calculate the no. of tons of coal fired per hr for a gross efficiency of 85%. Answer: A A. 4.889 tons/hr B. 5.897 tons/hr C. 3.267 tons/hr D. 2.675 tons/hr. 6. A water tube boiler has a capacity of 1000 kg/hr of steam.Get Price
For example: (i) Central thermal power plants, captive power plants based on coal. (ii) Nuclear power plants. Steam out Water in Q5–2 Boiler q1–2 = w1–2 (h2 – h1) + (kE2 – kE1) + PE2 – pE1) – q1–2 = h2 – h1 Heat is lost by the system to the cooling water q1–2 = h1 – h2 2. Steam flow rate = 3600Kg/hr = 3600/3600 = 1 Get Price
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